in part d, the reduction equation is: O3(g)+H20(l)+2e- --> O2(g)+2OH-
Why does OH-(aq) come before O3(g),O2(g) in the cell diagram, when it is a product of the half reaction?
6M.13 in 7th edition
Moderators: Chem_Mod, Chem_Admin
-
Chem_Mod
- Posts: 23858
- Joined: Thu Aug 04, 2011 1:53 pm
- Has upvoted: 1253 times
Re: 6M.13 in 7th edition
For the cathode side of the cell diagram, aqueous compounds are written before gaseous compounds. I am unclear about what you are asking in the second part of your question.
Return to “Galvanic/Voltaic Cells, Calculating Standard Cell Potentials, Cell Diagrams”
Who is online
Users browsing this forum: No registered users and 12 guests