14.11d (6th Edition)

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AnnaYan_1l
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14.11d (6th Edition)

Postby AnnaYan_1l » Wed Feb 27, 2019 10:58 pm

Hi! So, I am working on 14.11d, and I am a bit confused.

The question is: Pt(s)|O2(g)|H+(aq) || OH-(aq)|O2(g)|Pt(s) and it asks to write the half-reactions and the balanced equation for the cell reaction...

When I was writing the half-reaction for the anode side, I originally wrote it H+ -> O2, since it seems like the compound closest to the salt bridge is usually the reaction for a reduction reaction. Why is it O2 -> H+?

Thanks!

Kate Chow 4H
Posts: 61
Joined: Fri Sep 28, 2018 12:28 am

Re: 14.11d (6th Edition)

Postby Kate Chow 4H » Thu Feb 28, 2019 8:00 pm

In cell potential diagrams, the format is always written as reactants then products, so the O2 comes first and is therefore the reactant.


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