K


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Dina Geotas 4A
Posts: 61
Joined: Fri Sep 28, 2018 12:29 am

K

Postby Dina Geotas 4A » Mon Mar 04, 2019 3:11 pm

When K is 0, <1, and >1, what is ∆G's sign??

Kristen Kim 2K
Posts: 70
Joined: Fri Sep 28, 2018 12:16 am

Re: K

Postby Kristen Kim 2K » Mon Mar 04, 2019 3:12 pm

K = 0 then delta G = 0
K < 1 then delta G > 0
K > 1 then delta G < 0

Jonny Schindler 1A
Posts: 30
Joined: Fri Sep 28, 2018 12:20 am

Re: K

Postby Jonny Schindler 1A » Mon Mar 04, 2019 3:16 pm

When delta G is zero the equation is at equilibrium so K=1.

varunhariharan
Posts: 30
Joined: Mon Jan 07, 2019 8:16 am

Re: K

Postby varunhariharan » Mon Mar 04, 2019 5:32 pm

This can be seen using ΔG = -RTlnK

When K>1, then lnK is positive, and ΔG is negative.
When K<1, then lnK is negative, and ΔG is positive.

Kevin Tang 4L
Posts: 83
Joined: Fri Sep 28, 2018 12:28 am

Re: K

Postby Kevin Tang 4L » Tue Mar 05, 2019 1:52 pm

Using the equation ΔG = -RTlnK.
ln 1=0 thus when K=1, ΔG = 0

Jack Hewitt 2H
Posts: 67
Joined: Fri Sep 28, 2018 12:27 am

Re: K

Postby Jack Hewitt 2H » Tue Mar 05, 2019 1:55 pm

K = 0 ; delta G = 0
K < 1 ; delta G > 0
K > 1 ; delta G < 0


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