## Textbook Problem 6O #1

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Rami_Z_AbuQubo_2K
Posts: 89
Joined: Thu Jun 07, 2018 3:00 am

### Textbook Problem 6O #1

Why do we have to use 2H2O-->O2 + 4H + 4e- in this problem. Also where do they get the value of 1.23 for Enaught and why is Ni2+ half reaction the cathode and not the anode even though we have typically tried to create the most positive E.

aisteles1G
Posts: 117
Joined: Fri Sep 28, 2018 12:15 am

### Re: Textbook Problem 6O #1

I was also really having trouble with this and found this old post: viewtopic.php?t=3354 the explanations in the answers are pretty helpful in understanding the Enaught value!

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