## 15.9 6th edition

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

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### 15.9 6th edition

15.9 Express the units for rate constants when the concentrations are in moles per liter and time is in seconds for (a) zero-order reactions; (b) first-order reactions; (c) second order reactions.
What does it mean for a reaction to have zero-order?

Neil Hsu 2A
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Joined: Fri Sep 28, 2018 12:16 am

### Re: 15.9 6th edition

Zeroth order reactions mean that changing the concentration of any reactant will not affect the rate at which the reaction proceeds. In terms of the question, the rate law is rate = k, so k has units of M/s

Matthew Choi 2H
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Joined: Fri Sep 28, 2018 12:18 am

### Re: 15.9 6th edition

Normally, you will see that changing the concentration of the reactants will affect the rate of the reaction. However in a zero-order reaction, changing the concentration will not change the rate. Therefore, the rate will equal the k constant. In order for the rate to have the units of mol/(L*s), k will have the units mol/(L*s).

tierra parker 1J
Posts: 61
Joined: Fri Sep 28, 2018 12:17 am

### Re: 15.9 6th edition

zero order reaction means that the concentration the reactant has no effect on the rate of the reaction so even if you increase the amount of reactant the reaction will proceed at the same time. the unit for the rate constant will be M/s