## activation energy

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

Samantha Jimenez 4k
Posts: 29
Joined: Fri Sep 28, 2018 12:21 am

### activation energy

How would we find the activation energy, given both rate constants and temperatures?

305113590
Posts: 66
Joined: Fri Sep 28, 2018 12:28 am

### Re: activation energy

Because we know that K=Ae^(-Ea/RT), we could derive it in such way that we can find the slope of the activation energy linearly.

We can receive the equation attached to this post. We plug in our rate constants and the initial and final temperatures such that we can receive our Ea
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Posts: 63
Joined: Fri Sep 28, 2018 12:19 am

### Re: activation energy

There are some hw problems that go over this towards the end of the chapter, but basically you can derive the equation by adding the equations together to get rid of A.

Karyn Nguyen 1K
Posts: 72
Joined: Fri Apr 06, 2018 11:04 am

### Re: activation energy

How do we determine which one is K1 and which one is K2?