Ranking in order of increasing reducing power

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Kassidy Tran 1E
Posts: 77
Joined: Fri Sep 28, 2018 12:15 am

Ranking in order of increasing reducing power

Postby Kassidy Tran 1E » Sun Mar 10, 2019 3:22 pm

How do you rank an element in order from increasing reducing power going from their neutral state to second oxidation state? For example, for the elements Pt, Pb, Cu.

Timothy_Yueh_4L
Posts: 57
Joined: Fri Sep 28, 2018 12:28 am

Re: Ranking in order of increasing reducing power

Postby Timothy_Yueh_4L » Sun Mar 10, 2019 3:41 pm

You would rank them according to decreasing standard reduction potential (+ --> -). This is because the lower the reduction potential, the stronger the oxidation potential therefore when finding the element with the strongest reducing power we want the element with the highest reduction potential which is best at driving the reduction half reaction.

Edward Xie 2E
Posts: 63
Joined: Fri Sep 28, 2018 12:23 am

Re: Ranking in order of increasing reducing power

Postby Edward Xie 2E » Sun Mar 10, 2019 3:50 pm

For increasing reducing power, you would list them in order of decreasing reduction potential.

Pt (Eo = 1.20 V) < Cu (Eo = 0.34 V) < Pb (Eo = -0.13 V)

Abby-Hile-1F
Posts: 46
Joined: Fri Sep 28, 2018 12:16 am

Re: Ranking in order of increasing reducing power

Postby Abby-Hile-1F » Sun Mar 10, 2019 7:28 pm

How do you tell if something will have reducing or oxidizing power, I know it depends on the sign of E, but which is which?

Joonsoo Kim 4L
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Joined: Fri Sep 28, 2018 12:29 am

Re: Ranking in order of increasing reducing power

Postby Joonsoo Kim 4L » Thu Mar 14, 2019 10:23 pm

I believe that if E(red) is strongly positive, the reaction favors reduction, so it would be a good oxidizing agent. Contrarily, if E(red) is strongly negative, the reaction favors oxidation, so it would be a good reducing agent.

Abby-Hile-1F
Posts: 46
Joined: Fri Sep 28, 2018 12:16 am

Re: Ranking in order of increasing reducing power

Postby Abby-Hile-1F » Fri Mar 15, 2019 8:04 pm

Joonsoo Kim 4L wrote:I believe that if E(red) is strongly positive, the reaction favors reduction, so it would be a good oxidizing agent. Contrarily, if E(red) is strongly negative, the reaction favors oxidation, so it would be a good reducing agent.

Ok yeah that makes sense, thank you!

Nghi Nguyen 2L
Posts: 61
Joined: Fri Sep 28, 2018 12:18 am

Re: Ranking in order of increasing reducing power

Postby Nghi Nguyen 2L » Fri Mar 15, 2019 9:14 pm

decreasing reduction potential, which means increasing oxidation reaction, which means increasing reducing power


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