k & K
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Re: k & K
k in electro should be Boltzmann's constant while k in kinetics is a number unique to each reaction scaling how quickly the reaction proceeds.
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Re: k & K
To add to the previous answer, K in thermodynamics is the equilibrium constant, which describes the concentrations of reactants and products at equilibrium, and doesn’t have anything to do with the speed of the reaction.
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Re: k & K
isn't boltzmann's constant used to calculate entropy with the number of possible states of a molecule and the number of molecules?
rate constants and boltzmann are entirely different things.
rate constants and boltzmann are entirely different things.
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Re: k & K
k is Boltzmann constant, which is equal to 1.38064852 × 10^-23 m2 kg s^-2 K^-1. K is the equilibrium constant of a reaction, which is calculated by the concentration of the products over concentration of the reactants.
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Re: k & K
k is the Boltzmann rate constant while K is the equilibrium constant for a certain reaction.
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Re: k & K
I am sure the question will tell us to use the k as a rate constant in kinetics in the question, whereas the k Boltzmann constant will be used to calculate the entropy. K will be given in an acids and base question. It is based off of context.
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Re: k & K
The difference is that k is Boltzmann's constant, while K is the equilibrium constant for a given reaction.
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Re: k & K
In kinetics, k is the rate constant, whereas K is the equilibrium constant. Also, K = k/k', which means the the equilibrium constant is equal to the ratio of rate constants of the forward (k) and the reverse (k') elementary reactions.
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Re: k & K
k is the rate constant so it's basically an indicator of how fast the reaction will happen. K is the equilibrium constant that tells you the ratio of products to reactant concentrations when the reaction is at equilibrium. Based on the relationship between k and K, we can determine that the forward reaction's rate constant, k will be larger than the reverse reaction rate constant if K (equilibrium constant) is larger than 1.
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Re: k & K
It is also important to note that K can be figured out by taking the ratio of the forward reaction K to the reverse reaction K
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Re: k & K
Will there be a clear indication of 'k' and 'K' on the final? Such as bolding one over the other. Thanks.
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Re: k & K
Melissa Villanueva1K wrote:Will there be a clear indication of 'k' and 'K' on the final? Such as bolding one over the other. Thanks.
Do you mean on the constants and equations sheet?
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Re: k & K
Melissa Villanueva1K wrote:Will there be a clear indication of 'k' and 'K' on the final? Such as bolding one over the other. Thanks.
I think in order to avoid confusion, it may be written out for us along with the variable e.g. "the rate constant, k,..."
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Re: k & K
K is the equilibrium constant and kr is the rate constant, symbolizing different constant values with different meanings, applied in different equations but they are related. K is equal to the overall forward rate constant over the reverse rate constant because at equilibrium the forward and reverse rates (not the constants) are equal.
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