## k(1)/k(-1)

Arrhenius Equation: $\ln k = - \frac{E_{a}}{RT} + \ln A$

David Sarkissian 1K
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### k(1)/k(-1)

What does k(1)/k(-1) mean? Why do we use it in our rate law? Mostly I just can't conceptualize what it means or how we find k(-1).

Porus_Karwa_2E
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Joined: Fri Sep 28, 2018 12:24 am

### Re: k(1)/k(-1)

k(1)/k' =K (equilibrium constant)
k' is the reverse or second process

MichelleRamirez_2F
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Joined: Fri Sep 28, 2018 12:28 am

### Re: k(1)/k(-1)

k' is referring to the reverse reaction.

Gillian Ward 1F
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### Re: k(1)/k(-1)

k is referring to the rate of the forward reaction while k' is referring to the rate of the reverse reaction

Matthew Casillas 1C
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### Re: k(1)/k(-1)

If we want to express both can we use Kc? For example, can we use Kc when doing pre-equilibrium calculations?