Hw problem 1.13

(Wien's law: $T\lambda _{max}=\frac{1}{5}C_{2}$ )

804637502
Posts: 10
Joined: Fri Sep 25, 2015 3:00 am

Hw problem 1.13

this question states: "use the Rydberg formula for atomic hydrogen to calculate the wavelength of radiation generated by the transition from n=4 to n=2."

I am not sure why the answer I am getting is a number to the power of negative 19 when the answer in the book is 486 nm.
thanks

Chem_Mod
Posts: 19135
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 818 times

Re: Hw problem 1.13

It sounds like what you've calculated is the energy of the radiation emitted, while what the question asked for was the wavelength. You could use $\lambda=\frac{h*c}{E}$ or $\lambda=\frac{c}{\nu}$ to find the correct answer.

404639305
Posts: 15
Joined: Fri Sep 25, 2015 3:00 am

Re: Hw problem 1.13

Also, you might have left your answer in meters which is why you have the negative exponent. Multiply your answer by 1.0x10^9, and that should get your answer to nanometers.