## Photons

$c=\lambda v$

AngieGarcia_4F
Posts: 120
Joined: Thu Jul 25, 2019 12:17 am

### Photons

Increasing intensity means you increase the number of photons right? And if one photon interacts with one electron, then why doesn't increasing intensity lead to increased electrons emitted? And why doesn't more photons equal more energy?

Justin Seok 2A
Posts: 104
Joined: Sat Aug 24, 2019 12:15 am

### Re: Photons

Technically, increasing the intensity would actually increase total energy, as there are simply more electrons being emitted. However, what intensity doesn't change is the amount of energy per photon/electron being emitted, as that depends on frequency only and is based on the equation E = hv.

Michael Nguyen 1E
Posts: 120
Joined: Sat Aug 17, 2019 12:17 am

### Re: Photons

Increasing intensity does increase the number of electrons emitted, but only if the energy per photon is greater than the threshold energy of the metal. Also, more photons does mean there is more total energy, but electrons are only emitted if the threshold energy is surpassed.

SarahSteffen_LEC4
Posts: 67
Joined: Sat Aug 24, 2019 12:17 am

### Re: Photons

By increasing intensity, more electrons may be emitted, but that does not mean that their energies have increased. Frequecy would need to increase for this to happen.

Nare Nazaryan 1F
Posts: 101
Joined: Fri Aug 09, 2019 12:17 am

### Re: Photons

Increasing intensity doesn't lead to electrons being emitted, because increasing the intensity only increases the number of photons instead of the energy that each photon has. So in the photoelectric experiment, it's best to see light in terms of photons, since the energy of photons is what helps emit the electrons. In order to get a higher energy, we need a higher frequency, which means shorter wavelength. Then, once we have found the correct wavelength we can intensify those waves of light, since each proton now has enough energy to emit an electron.

DMuth_1J
Posts: 63
Joined: Thu Jul 11, 2019 12:15 am

### Re: Photons

If you already have a light source that is having a photon interact with an electron, it means that the photon has the frequency (its energy is above or at the threshold energy) required to eject an electron from that surface. Therefore, when you increase the intensity of that same light source, there will be more electrons emitted. However, if the light source is not of a high enough frequency (its energy does not meet the threshold energy), increasing the intensity simply throws more photons at the surface to which the photons have no effect.

If the light is having a photon interact with an electron, increasing the intensity DOES emit more electrons.

Hannah Romano 4D
Posts: 55
Joined: Sat Aug 24, 2019 12:18 am

### Re: Photons

Increasing the intensity WILL increase the QUANTITY of e- ejected. This is because increasing the intensity, or amplitude, basically means you are increasing the number of photons that will strike the metal at a certain frequency. While only increasing the frequency will increase the energy on an individual e-, increasing the intensity/amplitude will increase the number of e- emitted. Each individual photon interacts with each individual e-. Therefore, more photons correlates to more e-.

Astrid Lunde 1I
Posts: 103
Joined: Sat Sep 07, 2019 12:16 am

### Re: Photons

A photon is just the name for a quantum of light, right?