## "Work Function" (from Post-Assessment Module)

$c=\lambda v$

Chloe Alviz 1E
Posts: 102
Joined: Sat Aug 17, 2019 12:17 am

### "Work Function" (from Post-Assessment Module)

My question refers to a problem from the post-assessment module:

"Light hits a sodium metal surface and the velocity of the ejected electron is 6.61 x 10^5 ms-1. The work function for sodium is 150.6 kJ mol-1...."

In this question, what does the "work function" refer to? Is it supposed to be the threshold energy?

Chem_Mod
Posts: 19160
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 831 times

### Re: "Work Function" (from Post-Assessment Module)

Work function (kJ/mol) is the energy needed to eject one mole of e- from the metal surface.

Light is hitting the sodium metal, and ejected e- have a specified velocity, indicating it has kinetic energy. The energy of the incoming light is used to eject e- (work function), and any leftover energy goes towards kinetic energy.

Jocelyn Thorp 1A
Posts: 103
Joined: Wed Sep 18, 2019 12:20 am

### Re: "Work Function" (from Post-Assessment Module)

Chem_Mod answered your question already but if you want the equation it's used in, here you go

The work function is the Φ in the equation $\frac{1}{2}m_{e}v^{2}=h\nu -\phi$ that relates the kinetic energy of the ejected electron to the energy supplied by a photon and the work function.

005206171
Posts: 107
Joined: Wed Sep 18, 2019 12:20 am

### Re: "Work Function" (from Post-Assessment Module)

In the context of the photoelectric effect and experiment, the work functions describe the minimum energy a photon needs to knock off an electron so that the electron can overcome it's an attraction to the plate. Some electrons are more attracted to the metal than others. Those with the highest max kinetic energy will have to use the least amount of energy from the photon to pop off the metal.

Shrayes Raman
Posts: 129
Joined: Sat Jul 20, 2019 12:15 am

### Re: "Work Function" (from Post-Assessment Module)

The work function refers to the energy required to eject an electron. This is subtracted from the initial energy of the incoming photon to find the energy of the photon as it leaves

### Who is online

Users browsing this forum: No registered users and 2 guests