percent yield

[bellaha4F]

should we always show the percent yields in the limiting reactant problems, or just when it's specifically asked?

[405335722]

Hi!

You can only do percent yield problems if they give you the experimental data so if they give it to you I would do it just in case.

Remember percent yield is,

100(actual yield/theoretical yield)= percent yield.

[Charysa Santos 4G]

It depends on what you are given. They will usually ask for it, or if they give you the experimental data for something like a problem where you have to find the empirical formula, then you should calculate it to help you with the final answer.

[Khushboo_3D]

It depends on what's given to us. Usually to find the percent yield you would need the actual yield. Through limiting reaction problems, you can usually only find the theoretical yield.

[jisulee1C]

Usually the problem will ask specifically for the percentage yield and if it is not asked for then you don't need to calculate it.

[Kallista McCarty 1C]

You only have to put it if they specifically ask for it in the question!

[KMenjivar_3A]

No, limiting does associate with finding the percent yield; however, calculating the % yield is unnecessary unless the question specifically asks us to solve it.

[ranqiao1e]

We only need to worry about percent yield when the problem asks us to do so. However, while doing experiments, we should always expect a difference between the theoretical and the actual

[CynthiaLy4F]

You don't have to worry about finding the percent yield unless the question specifically asks for you to find it.

[Nick Fiorentino 1E]

I believe you only find the percent yield if it is asked in the question, but there may be some scenarios where you need it for a step in the problem. Also, questions don't always explicitly ask what they want you to find so be aware of that

[Rebecca Remple 1C]

Hi Bella,

I agree with the previous posters that you do not have to show percent yield on limiting reactant problems. In fact, the yield you calculate using the limiting reactant would actually be the theoretical/maximum yield! Basically, the limiting reactant determines the maximum amount of product you can get, no matter how much of the excess reactant you have. For example, let's say that 1A + 2B -> 3C. If you have 1 mol of A, it doesn't matter if you have 2 or 200 mol B, because your maximum yield will always be 3 mol C. If you conducted this experiment using these exact measures of reactants and wound up with 2 mol C, then that would be the actual yield. In this case, the percent yield would be (2/3) * 100%, or about 66.67%. I hope this helps!

-Rebecca