## Momentum

$\Delta p \Delta x\geq \frac{h}{4\pi }$

KDang_1D
Posts: 127
Joined: Fri Aug 30, 2019 12:15 am
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### Momentum

What is the significance of momentum in the Heisenberg Indeterminacy equation? Why not write the formula in terms of $\Delta v$ if you can't interpret anything from $\Delta p$ unless you convert it to velocity using p=mv?

Khushboo_3D
Posts: 60
Joined: Wed Sep 18, 2019 12:19 am

### Re: Momentum

The whole idea behind bringing momentum into the picture is to emphasize the fact that an uncertainty in velocity results in an uncertainty in momentum, since we know the mass of the object and it does not change. Moreover, we need the change in momentum to calculate the uncertainty because, according to Heisenberg's uncertainty indeterminacy equation:
(Indeterminacy in momentum) X (Indeterminacy in position) >= h/ 4 pi

Ziyan Wang 3J
Posts: 51
Joined: Wed Sep 18, 2019 12:22 am

### Re: Momentum

Because for some objects (such as photon), they have no mass, but they have momentum. It will be non-sense to write it into delta x * m * delta v>= h/4pi for those objects.