Joules units

[Jedrick Zablan 3L]

Hello can anyone explain to me why Joules in Planck's Constant is kg x m^2 x s? Thanks.

[andrewcj 2C]

In the formula E = hv, E is measured in Joules and v is measured in Hz, or s^-1. By dimensional analysis, we see that by multiplying kg x m^2 / s by 1/s, we get a units of kg x m^2/s^2. Since Joules is a measure of energy/work, it is equivalent to force x distance. Breaking this down further, force is equivalent to mass x acceleration, which results in units of kg x m/(s^2). Multiplying this by distance gives you kg x m^2/s^2, which is the same as the units for the right side of the E = hv equation.

[KaleenaJezycki_1I]

Hello can anyone explain to me why Joules in Planck's Constant is kg x m^2 x s? Thanks.

Joules in Planck's Constant is expressed as such because it helps for unit cancellation, depending on what you are solving for one of these two expressions will be easier to visually see how you obtain your final units.

[Jenna Ortiguerra 4G]

Joules in Planck's Constant can either be expressed by 6.626 x 10^-34 J.S. or 6.636 * 10^-34 kg*m^2*s^-1. Typically, choosing between 6.636 * 10^-34 kg*m^2*s^-1 and 6.626 x 10^-34 J.S. is situational, in which the one that would provide the easiest cancellations would be the best option to use.

[505106414]

So the units are essentially equivalent to each other?

[Nathan Nakaguchi 1G]

Planck's Constant's units are J * s (joules times seconds) not necessarily just joules, thats why the Planck's units are (kg m^2 s^-2) * (s) = kg m^2 s^-1.

[Mai V 4L]

Does anyone have a video they think is aa good reference for this topic?