HW 2A.21d

[Amy Pham 1D]

Why is the electron configuration for Ag: [Kr]4d10 5s1 instead of [Kr]4d9 5s2? By the rules that we were taught, shouldn't it be the latter?

Following this, I understand that starting with the correct electron configuration makes the configuration for Ag+: [Kr]4d10, with no unpaired electrons. I'm just confused as to how we were supposed to know the original electron configuration for Ag.

[Maya Serota 3G]

I am also confused about this question. I looked it up and the answer differs on various websites. Anyone who can clarify would be much appreciated!

[DTingey_1C]

I believe Lavelle mentioned this odd configuration along with one other one that I am forgetting right now. He said that these two configurations are anomalies that we just have to memorize without much further explanation. Some areas of chemistry (and science in general) are proven experimentally but can't be explained. This is probably one of those areas. Sorry if this is a limited explanation but this is all I remember him saying.

[jvera4b]

I believe Lavelle mentioned this odd configuration along with one other one that I am forgetting right now. He said that these two configurations are anomalies that we just have to memorize without much further explanation. Some areas of chemistry (and science in general) are proven experimentally but can't be explained. This is probably one of those areas. Sorry if this is a limited explanation but this is all I remember him saying.

Additionally I think it has to do with the fact that a half full d shell is more stable.

[Maya Gollamudi 1G]

Ag is one of the exceptions to the usual electron configuration pattern. Since a full d-shell is much more stable than a partially full d-shell (d9), the electron configuration becomes [Kr]4d10 5s1.

[Amy Pham 1D]

The two elements that he told us were exceptions were chromium (Cr) and copper (Cu), so I'm assuming silver would be another exception based on the fact that it is in the same group as copper?