1D.21

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Jessica Luong 3E
Posts: 42
Joined: Sat Aug 17, 2019 12:17 am

1D.21

Postby Jessica Luong 3E » Mon Oct 28, 2019 12:30 am

Write the subshell notation (3d, for instance) and the number of orbitals having the following quantum numbers: (a) n 5 5, l52; (b) n51,l50;(c) n56,l53; (d) n52,l51.

Julie Park 1G
Posts: 100
Joined: Thu Jul 25, 2019 12:15 am

Re: 1D.21

Postby Julie Park 1G » Mon Oct 28, 2019 1:40 am

i think the question was mistyped but just for reference:
Write the subshell notation (3d, for instance) and the number of orbitals having the following quantum numbers:
a. n=5, l=2 (5d, five)
b. n=1, l=0 (1s, one)
c. n=6, l=2 (6f, seven)
d. n=7, l=3 (2p, three)

Know that
l = 0 corresponds to the s-orbital
l = 1 corresponds to the p-orbital
l = 2 corresponds to the d-orbital
l = 3 corresponds to the f-orbital

Know that
s-orbital = 1 orbital, total of 2 e-
p-orbital = 3 orbitals, total of 6e-
d-orbital = 5 orbitals, total of 10e-
f-orbital = 7 orbitals, total of 14e-
Each orbital has 2 e-

Example using a (n=5, l=2)
--> Since l=2, we can assume this is a d-orbital. We know that the d-orbital has 5 orbitals, each containing 2 electrons

cassidysong 1K
Posts: 100
Joined: Fri Aug 30, 2019 12:15 am

Re: 1D.21

Postby cassidysong 1K » Sun Nov 03, 2019 10:05 pm

For reference for l,
l=0 ---> s orbital
l=1 ---> p orbital
l=2 ---> d orbital
l=3 ---> f orbital (we don't really need to know this)
the principal quantum number, n, just needs to be in the front so,
n=5 l=2 ---> 5d
n=1 l=0 ---> 1s
n=6 l=3 ---> 6f
n=2 l=1 ---> 2p


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