2C.9

[ayushibanerjee06]

For 2C.9, when I did the correct Lewis Structure, I did not get a formal charge of 0 for Xe. What am I doing wrong?

[ayushibanerjee06]

Sorry, I meant 2C.11 part c

[Brooke Yasuda 2J]

Remember that formal charge equation is #valance electrons - ((bonding electrons/2) + electrons in lone pairs)

[Baoying Li 1B]

You can count the valences of electron of the Lewis structure and check that if it's equal to the number of valence of electrons you have calculated. Since there are 42 valences of electron in XeOF2, Xe has one lone pair.

[BeylemZ-1B]

If your lewis structure is correct, there will be a double bond between Xe and O, single bonds between each F and the Xe, and a lone pair on the central atom, Xe.

Now you take the equation for formal charge = V - (L + 1/2*B)
Since Xe is in the very last group it has a value of V = 8.
There are 2 lone pairs (L=2) and 12 electrons in bonded pairs (1/2*12=6)

8 - (2+6) = 0.