Kinetic Energy Uncertainty Conversion


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Trent Yamamoto 2J
Posts: 111
Joined: Sat Aug 17, 2019 12:18 am

Kinetic Energy Uncertainty Conversion

Postby Trent Yamamoto 2J » Sun Nov 03, 2019 8:45 pm

In the Heisenberg Indeterminacy Module, question 22 asked for the uncertainty in kinetic energy (which I was able to calculate) and the conversion of that into moles. How would I do that?

Kevin Antony 2B
Posts: 99
Joined: Sat Sep 07, 2019 12:16 am

Re: Kinetic Energy Uncertainty Conversion

Postby Kevin Antony 2B » Sun Nov 03, 2019 9:01 pm

From what I gather, you know have energy per electron. We know there are 6.022 x 10^23 electrons in a mol. If you divide by Avagadro's number you should get energy per mol.

Trent Yamamoto 2J
Posts: 111
Joined: Sat Aug 17, 2019 12:18 am

Re: Kinetic Energy Uncertainty Conversion

Postby Trent Yamamoto 2J » Sun Nov 03, 2019 10:57 pm

Kevin Antony 1J wrote:From what I gather, you know have energy per electron. We know there are 6.022 x 10^23 electrons in a mol. If you divide by Avagadro's number you should get energy per mol.


That makes sense, thank you!

britthanul234
Posts: 51
Joined: Wed Sep 18, 2019 12:21 am

Re: Kinetic Energy Uncertainty Conversion

Postby britthanul234 » Wed Nov 13, 2019 11:36 am

There are 6.022 x 10^23 electrons in a mol. If you divide by Avagadro's number you get energy per mol.


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