## 4b practice midterm

$c=\lambda v$

yazminedesan1F
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### 4b practice midterm

" A newly designed laser pointer with a certain frequency is pointed at a sodium metal surface. An electron is ejected from the metal surface with wavelength 1.10 nm. What is the frequency of the light from the laser pointer? The work function of sodium is 150.6 kJ∙mol-1"

So sometimes to find frequency we use the equation (c(speed of light)/wavelength), which is what I when given wavelength, however I know that sometimes we also use the equation h*v(frequency)-work function=1/2*m*velocity^2. In what circumstances do you use either equation because I'll use (c(speed of light)/wavelength) and it ends up wrong to find frequency. This specifically pertains to question 4b on the practice midterm.

Chem_Mod
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### Re: 4b practice midterm

$c = \lambda \nu$ is for electromagnetic radiation (light) only. The wavelength mentioned in this problem is that for a moving electron (something with mass), so you have to use de Broglie equation to get the desired information.

Samantha Castro 1D
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### Re: 4b practice midterm

I believe that you have to use the De Broglie equation for this problem, since the wavelength is given for a moving electron in this problem, in order to get the correct answer.

Alexis Bravo 1D
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### Re: 4b practice midterm

How does work function fit into the problem? Is it only necessary in order to show us that this is a moving electron?

Chem_Mod
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### Re: 4b practice midterm

It is a photoelectric question so you will need the photoelectric equation. You just need to use the de Broglie equation to get the velocity of the electron, hence the kinetic energy of the ejected electron in order to solve the entire problem.

EllenRenskoff-1C
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### Re: 4b practice midterm

Do we need to take into account the fact that it says the work function is kJ*mol^-1? I know we have to convert the energy to J, but do we need to cancel out the moles?

Chem_Mod
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### Re: 4b practice midterm

EllenRenskoff-1C wrote:Do we need to take into account the fact that it says the work function is kJ*mol^-1? I know we have to convert the energy to J, but do we need to cancel out the moles?

Yes, use Avogadro's number to do so.

Jennifer Tuell 1B
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### Re: 4b practice midterm

I am still very confused and keep getting the wrong answer for this problem. I found v from wavelength=h/mv and then did 1/2m (mass of an electron) v^2 plus the converted work function and got 3.00x10^14

Jennifer Tuell 1B
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### Re: 4b practice midterm

Update: I forgot to add the kinetic energy to the work function before diving by h!

Alicia Beebe
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### Re: 4b practice midterm

I struggled with this one because I wasn't sure how to convert the work function. I just had to remember that it was in kJ/mol, and needed to be in J/ atom. This was confusing for me because it is normally just written as J. So I had to multiply it by 1000 and divide by 6.022*10^23

brennayoung
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### Re: 4b practice midterm

How do we find the frequency once we've found the Energy using E = phi + 1/2mv^2 ? because the ones that have frequency we aren't supposed to use if there is mass involved i thought

Lauren Tindall
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### Re: 4b practice midterm

For this problem, you must use the De Broglie equation. De Broglie is typically used for an electron's wavelength with mass, while c=λν or E=hv is used for massless particles, like photons.