Rydberg equation
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Rydberg equation
Why are we not allowed to use the Rydberg equation frequency = R( 1/n1^2 - 1/n2^2)?
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Re: Rydberg equation
I don't think it's that we're not allowed to. Just that Lavelle would prefer that we use -hR/n1^2.
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Re: Rydberg equation
It's preferred because it is easier to understand conceptually with the way he taught us in class.
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Re: Rydberg equation
The Rydberg equation doesn't show different energy levels and how to conceptually get from one level to another one. Thus, it's easy to either get mixed up with emission vs absorption or to just completely forget to concepts behind the formula.
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Re: Rydberg equation
You can use that equation, but the energy version that's given by Dr. Lavelle explains the concept better for me.
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Re: Rydberg equation
The equation you stated is a derivation of -hr/nfinal^2 - (-hr/ninitial^2). If you factor out the -hr you should get an equation similar to what you posted. As the others stated the equation we learned in class is easier to see conceptually.
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Re: Rydberg equation
We are actually totally allowed to use the Rydberg equation, whereas using the (final - initial) form of the the Rydberg equation could give us a better understanding of the concept and therefore what we are doing. And I believe that using the form of equation recommended by professor Lavelle eliminates the probability of confusing the final state with the initial state.
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Re: Rydberg equation
You're allowed to use both, yet it depends on which one explains the concept better for you.
Re: Rydberg equation
I think we're not allowed to because it doesn't fully show out the concept. This class is very conceptual, therefore the whole concept of each problem is expected to be shown in our work.
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