3 posts • Page 1 of 1
In this case, both molecules have both induced dipole induced dipole and dipole dipole intermolecular forces, but because pentane is a much smaller molecule, it has less electrons and a smaller surface area. Because of this, pentane will have weaker induced dipole induced dipole forces, and therefore, have a lower boiling point.
Although both molecules are composed of the same atoms, they have different structures which impacts the types of bonds they make. Both molecules create induced dipole-induced dipole bonds, but the strength of these forces differ because of the size of the molecules. Pentane is a smaller molecule so it has a stronger attractive on its electrons, making it less polarizable. Therefore, it will have a weaker induced dipole-induced dipole force, which requires less energy to break the bonds, creating a lower boiling point.
Who is online
Users browsing this forum: No registered users and 0 guests