How to know which angles are smaller

[zfinn]

in a VSEPR shape with more than one angle size, i.e. seesaw, would all the angles decrease because of the lone pair (so angles are <90, <120, <180)? or do just the angles next to the lone pair bonding region decrease?

[Montana James 4G]

The lone pair pushes the other regions of electron density closer to each other, making the bond angles smaller. but we can only do this qualitatively, we don't know exactly how much they change.

[Leila_4G]

What are the angles of the AX2E VSEPR formula? I think this is either a bent shape or trigonal planar but I'm not sure

[Leila_4G]

Also, what are the angles of AX5E (which I think is a square pyramidal shape)?

[Dakota Walker 1L]

Square pyramidal shapes have slightly less than 90 degree angles.

[Kishan Shah 2G]

@Leila: The shape of AX2E is bent. The bond angles are 120 degrees. For AX2E2 it is still bent, but the bond angles are 109.5 degrees since the two lone pairs push the two atoms further away from them therefore decreasing the angle.

[Bita Ghanei 1F]

For seesaw, it would just be <90 and <120
for T-shaped, it would only be <90

[Sam McNeill 1E]

Just remember that anything with a lone pair has less than angles of the original parent electron configuration.

[Adelpha Chan 1B]

Also, what are the angles of AX5E (which I think is a square pyramidal shape)?

the bond angles of an octahedral are 90. Therefore, as there is a lone pair in AX5E, the shape is a square pyramidal and the resulting bond angles are <90