Bond angles

(Polar molecules, Non-polar molecules, etc.)

kpang_4H
Posts: 55
Joined: Fri Sep 20, 2019 12:17 am

Bond angles

How do you determine the bond angles for a seesaw shaped molecule?

Bilal Pandit 1J
Posts: 98
Joined: Wed Sep 11, 2019 12:16 am

Re: Bond angles

The bond angles are less than 120 and 90, as it would be a trigonal bipyramidal without the "top" electron, so the lone pair repulsion pushes down and makes the angles slightly less than they were originally with the trigonal bipyramidal shape.

Jasmine Summers 4G
Posts: 50
Joined: Wed Sep 18, 2019 12:17 am

Re: Bond angles

Yes, the bond angles are approximately 90, 120, and 180 degrees.

RasikaObla_4I
Posts: 100
Joined: Thu Jul 25, 2019 12:15 am

Re: Bond angles

The bond angles are less than 120 degrees on the equatorial and less than 90 degrees on the axial.

Simon Dionson 4I
Posts: 107
Joined: Sat Sep 14, 2019 12:17 am

Re: Bond angles

Visually, it's similar to a trigonal bipyramidal but you would have to remove one bonding pair. So it would be 90, 180, 120

SMIYAZAKI_1B
Posts: 63
Joined: Sat Aug 24, 2019 12:15 am

Re: Bond angles

It is hard to determine the exact angle of the seesaw shape because every element differs in size and as a result, we can never determine the exact angles unless you remember the bond angles. However, in general you can consider each angles of the trigonal bipyramidal decreased as seesaw’s bond angle.

htatshwe_3L
Posts: 15
Joined: Tue Oct 02, 2018 12:16 am

Re: Bond angles

For seesaw I just remember that its 4 bonds with one lone pair.

Caitlin Ciardelli 3E
Posts: 44
Joined: Wed Sep 18, 2019 12:19 am

Re: Bond angles

Another important concept to remember is that VSEPR cannot provide us the exact bond angle, just approximate if it will be greater or less than our key angles (90, 180, 109.5)