## Balancing This Equation

Ashley Osorio
Posts: 54
Joined: Thu Jul 11, 2019 12:17 am

### Balancing This Equation

Write a balanced combustion reaction for solid nicotine (C10H14N2). (Hint: The reaction produces N2 gas). How can we balance it when both sides don't have Oxygen? Or does it? How are we supposed to figure this out?

Ashley Osorio
Posts: 54
Joined: Thu Jul 11, 2019 12:17 am

### Re: Balancing This Equation

Since its a combustion, wouldn't it be C10H14N2+ O2--> N2

Michelle Le 1J
Posts: 50
Joined: Fri Aug 09, 2019 12:16 am

### Re: Balancing This Equation

All combustion reactions consist of O2 as one of the reactants and CO2 and H2O as the products. So for this reaction specifically, the reactants are C10H14N2 and O2, and N2, CO2, and H2O would be the products.

Jasmine Vallarta 2L
Posts: 102
Joined: Sat Aug 17, 2019 12:18 am

### Re: Balancing This Equation

When it says "combustion," it is implied that you must add "+ _O2" to the reactant side of the reaction

Michelle N - 2C
Posts: 117
Joined: Wed Sep 18, 2019 12:19 am

### Re: Balancing This Equation

Combustion always mean that one of the reactants is O2 and the products are CO2 + H2O. Sometimes, they will add in, like in this problem, an extra product.

AKhanna_3H
Posts: 104
Joined: Wed Sep 18, 2019 12:19 am

### Re: Balancing This Equation

Combustion reactions always have O2 as a reactant and H20 and C02 as products.

sbottomley3a
Posts: 50
Joined: Wed Sep 18, 2019 12:19 am

### Re: Balancing This Equation

Combustion reactions always indicate that the reactant will be burned in O2, and the products at minimum are CO2 and H2O, but there may be others, depending on what exactly was burned in oxygen.

anjali41
Posts: 109
Joined: Fri Aug 09, 2019 12:15 am

### Re: Balancing This Equation

An important step to remember is that combustion always involves Oxygen gas as a reactant, even though it is often not states in the problem. So always remember to add Oxygen gas to the chemical equation of a combustion reaction before balancing, and you should be good.

KaleenaJezycki_1I
Posts: 127
Joined: Sat Aug 17, 2019 12:18 am
Been upvoted: 2 times

### Re: Balancing This Equation

Ashley Osorio wrote:Write a balanced combustion reaction for solid nicotine (C10H14N2). (Hint: The reaction produces N2 gas). How can we balance it when both sides don't have Oxygen? Or does it? How are we supposed to figure this out?

Combustion reactions always are a compound +O2 and produce CO2+H20

So this should look like C10H14N2 +O2 ------> CO2+ H2O + N2 (Then you can balance it)

kendal mccarthy
Posts: 109
Joined: Wed Nov 14, 2018 12:22 am

### Re: Balancing This Equation

combustion equations always have O2 on the reactant side and CO2 and H2O on the other, sometimes N2 depending on the organic molecule. 2C10H14N2 +27O2 ------> 20CO2+ 14H2O + 7N2

annikaying
Posts: 94
Joined: Sat Sep 14, 2019 12:16 am

### Re: Balancing This Equation

Combustion implies that the reactant given is reacting with O2.

RBergtraun_3A
Posts: 41
Joined: Wed Feb 20, 2019 12:15 am

### Re: Balancing This Equation

You always add O2 when its a combustion reaction. Fire needs oxygen.