pH calcuations

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kpang_4H
Posts: 55
Joined: Fri Sep 20, 2019 12:17 am

pH calcuations

Postby kpang_4H » Sun Dec 01, 2019 6:00 pm

Are pH=-log(H+) and pH=-log(OH-) the only equations we need to know, regarding pH, for the final?

Samuel Tzeng 1B
Posts: 103
Joined: Sat Aug 24, 2019 12:15 am

Re: pH calcuations

Postby Samuel Tzeng 1B » Sun Dec 01, 2019 6:05 pm

I believe so

JonathanS 1H
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Joined: Thu Jul 11, 2019 12:17 am

Re: pH calcuations

Postby JonathanS 1H » Sun Dec 01, 2019 6:05 pm

Other than molarity calculations we did ad the beginning of the quarter, we have not done any other calculations with pH besides the ones you have mentions, so I assume so.

Bradley Whitworth 4B
Posts: 54
Joined: Sat Jul 20, 2019 12:17 am

Re: pH calcuations

Postby Bradley Whitworth 4B » Sun Dec 01, 2019 7:31 pm

Regarding concentrations and the equations related to acid/base reactions I imagine we'll probably have to know those equations about Kb and Ka.

IScarvie 1E
Posts: 66
Joined: Sat Aug 17, 2019 12:16 am

Re: pH calcuations

Postby IScarvie 1E » Sun Dec 01, 2019 8:09 pm

So far, yes

MBouwman_4A
Posts: 40
Joined: Wed Sep 18, 2019 12:21 am

Re: pH calcuations

Postby MBouwman_4A » Mon Dec 02, 2019 8:36 am

It may also be helpful to remember that pH + pOH = 14.

Callum Guo 1H
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Joined: Fri Aug 02, 2019 12:15 am
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Re: pH calcuations

Postby Callum Guo 1H » Mon Dec 02, 2019 8:47 am

I think so, unless he gives us another one

preyasikumar_2L
Posts: 101
Joined: Fri Aug 09, 2019 12:17 am

Re: pH calcuations

Postby preyasikumar_2L » Mon Dec 02, 2019 8:55 am

That and pH+pOH=14, and perhaps equations relating to Ka.

DMuth_1J
Posts: 63
Joined: Thu Jul 11, 2019 12:15 am

Re: pH calcuations

Postby DMuth_1J » Mon Dec 02, 2019 9:16 am

Just to clarify, I think it's a typo, but pH= -log(H+) and pOH= -log(OH-). Make sure the pH is associated with the H+ / H3O+ and the pOH is associated with the OH-


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