Understanding Q

[briannam_1F]

When solving for Q do we omit solids and pure liquids, like when solving for K?

[Hiba Alnajjar_2C]

Yes; when solving for Q, you write the expression in the same exact way you would for K, omitting pure liquids and solids. The central difference between Q and K is that K represents the value at equilibrium, while Q is the ratio of products to reactants at any time during the reaction. But you would solve for the expression and value of Q in the same exact way.

[Callum Guo 1H]

Yes, solving for Q is the same way you would solve for K

[Daniel Toscano 1L]

Q is just ratio of the products and reactants when not in equilibrium, but is calculated the same way as K.

[BritneyP- 2c]

Just solve Q the way you would for K. K is at equilibrium and Q is at any time.

[Maya Pakulski 1D]

Yes, you would still omit solids and pure liquids. You also emit these when making an ICE table.

[RichBollini4G]

Yes; when solving for Q, you write the expression in the same exact way you would for K, omitting pure liquids and solids. The central difference between Q and K is that K represents the value at equilibrium, while Q is the ratio of products to reactants at any time during the reaction. But you would solve for the expression and value of Q in the same exact way.

Thank you!

[Jialun Chen 4F]

Correct. We perform the same calculation procedure when solving for Q and K.

[105335337]

Yes. Q and Kc are solved the completely same way. Q is just to tell if the reaction is at equilibrium or not.

[Abigail_Hagen2G]

They're solved exactly the same way.

[Juana Abana 1G]

Yes, you solve for Q the same way you would solve for K.

[nicole-2B]

You solve for Q the same way you solve for K.

[bellaha4F]

Q tells what point the reaction is at in relation to K, therefore it is solved the same way as K.

[Astrid Lunde 1I]

Yes you can solve Q the same way as you would solve K.

[805097738]

do you omit pure solids and liquids while solving for K too?

[Hiba Alnajjar_2C]

do you omit pure solids and liquids while solving for K too?

Yes, that is correct.

[Nare Nazaryan 1F]

Yes, solving for Q is the same thing as solving for K in terms of calculations (just that the reaction might not have reached equilibrium yet).

[stephaniekim2K]

Q is solved the same way as K, Q is just not at equilibrium.

[Shrayes Raman]

Q is calculated the same exact way as K just it can be anytime during reaction not just during equilibrium

[805097738]

To solve for Q we have to be given the values of each product and reactant, correct?