5G.9

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Karina Kong 2H
Posts: 98
Joined: Thu Jul 25, 2019 12:16 am

5G.9

Postby Karina Kong 2H » Sun Jan 12, 2020 10:30 pm

A sample of ozone, O3, amounting to .10 mol, is placed in a sealed container of volume 1.0 L and the reaction 2 O3(g) --> 3 O2 (g) is allowed to reach equilibrium. Without doing any calculations, predict which of the following will be different in the two containers at equilibrium. Which will be the same?

(a) amount of O2
(b) partial equilibrium of O2
(c) the ratio P O2/ P O3
(d) the ratio (P O2)^3/ (P O3)^2
(e) the ratio (P O3)^2/ (P O2)^3

alex_4l
Posts: 109
Joined: Thu Sep 26, 2019 12:18 am

Re: 5G.9

Postby alex_4l » Sun Jan 12, 2020 11:18 pm

Do you want the answers to this or is there some particular part of the problem you don't understand?

JNie1L
Posts: 5
Joined: Wed Oct 02, 2019 12:15 am

Re: 5G.9

Postby JNie1L » Sun Jan 12, 2020 11:29 pm

Only D and E will be the same. D and E are the expressions for K in both the forward and reverse reactions. K is always constant at a certain temperature, so those values will stay constant. A, B, and C are all dependent on the amount of moles or specific partial pressures and will differ between the two containers.

Ashley Nguyen 2L
Posts: 103
Joined: Sat Aug 17, 2019 12:18 am
Been upvoted: 1 time

Re: 5G.9

Postby Ashley Nguyen 2L » Sun Jan 12, 2020 11:34 pm

D and E will remain the same. Both are equation used to find K of the reaction in the forward and reverse direction. This ratio is a fixed constant.


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