5.35 finding partial pressure

Moderators: Chem_Mod, Chem_Admin

Sarah Blake-2I
Posts: 153
Joined: Fri Aug 30, 2019 12:16 am

5.35 finding partial pressure

Postby Sarah Blake-2I » Wed Jan 15, 2020 11:18 pm

In question 5.35, you are given a graph for A, B, and C. You are asked to write an equation and calculate the k value. I am just confused as to how I would find the exact partial pressure values for the K equation just by looking at the graph. I am unsure how to add the graph onto this post but the question I am referring is on pg. 438 and any explanation or help would be appreciated! Thank you!

Posts: 109
Joined: Sat Aug 24, 2019 12:17 am

Re: 5.35 finding partial pressure

Postby JasonLiu_2J » Wed Jan 15, 2020 11:22 pm

The y-axis on the graph gives the partial pressures in terms of kPa. Since 1pKA is equal to 0.01 bar, you can convert the equilibrium partial pressures in the graph from pKa to bars and use those partial pressures for the equilibrium constant equation.

Renee Grange 1I
Posts: 56
Joined: Fri Aug 30, 2019 12:16 am
Been upvoted: 1 time

Re: 5.35 finding partial pressure

Postby Renee Grange 1I » Thu Jan 16, 2020 12:01 am

We are given the partial pressure in pKa on the y axis. We can use the fact that 1 pKa = .01 bar when setting up the equilibrium constant.
Kp = (Pb)(Pc)^2/ (Pa)^2
Kp = (5/100)(10/100)^2/(18/100)^2
This gives up the equilibrium constant for the reaction.

Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 1 guest