6B.9

[Tiffany Chao 2H]

For 6B.9 i and ii, I keep getting different answers from the answer key. For i), I do the negative log of 1.50 and get the pH to be -0.176, [OH-] to be 6.67x10^-15, and pOH to be 14.17. This doesn't match the textbook that says pH = 0.176, [OH-] = 1.50x10^-14, and pOH = 13.824. I just don't know what I'm doing wrong.
Thanks

[Luyan Zhang - 2D]

Me too! I think the solution manual is wrong. Because taking the negative log of a number greater than one is negative. But the solution has a positive pH

[Minh Ngo 4G]

I didnt get the same ans as the back of the textbook either! For i i got -0.176 for pH instead of 0.176. There's probably a typo somewhere (??!), I hope

[Alondra]

I think on the class website there's a sheet about some errors in the solution manual. Not so sure though.