5.39

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gabbymaraziti
Posts: 111
Joined: Wed Sep 18, 2019 12:19 am

5.39

Postby gabbymaraziti » Sat Jan 18, 2020 9:18 pm

5.39 part b asks us to find the new equilibrium concentrations of two gases when the volume of the flask they are contained in is reduced by half. The original concentration of one of the gases was 0.020 M.
The solutions manual immediately finds that the new concentration of this gas is 0.040 M. How is this value found/what is the relationship here?

Prasanna Padmanabham 4I
Posts: 111
Joined: Thu Jul 25, 2019 12:17 am

Re: 5.39

Postby Prasanna Padmanabham 4I » Sat Jan 18, 2020 9:43 pm

The volume was halved. So initially, you had 0.020 mols/Liter and now you have 0.020 mols/0.5Liters = 0.040 M. Equilibrium concentration, values when trying to find Kc, deal with values in mols/Liter or molarity.


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