pH vs. pOH

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Delaney Smith 1C
Posts: 52
Joined: Thu Feb 28, 2019 12:15 am

pH vs. pOH

Postby Delaney Smith 1C » Sun Jan 19, 2020 4:53 pm

What do you do again when you are calculating pOH? Also, how do you know if you are calculating for a base or for an acid?

Catherine Daye 1L
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Joined: Wed Sep 11, 2019 12:16 am

Re: pH vs. pOH

Postby Catherine Daye 1L » Sun Jan 19, 2020 4:56 pm

To calculate pOH, you use the concentration of a base. Alternatively, you calculate the pH using the concentration of an acid. The question may also include a Ka or Kb value. The Ka indicates the equilibrium constant of an acid (uses concentration of hydronium ions), and the Kb indicates the equilibrium constant of a base (uses concentration of hydroxide ions).

Elena Bell 1C
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Re: pH vs. pOH

Postby Elena Bell 1C » Sun Jan 19, 2020 4:59 pm

The pOH is used when you have the concentration of OH- and is calculated the same way you would calculate pH. You can tell if you are calculating for an acid if it is giving off a proton and you are getting the H3O+ concentration. If it is a base, it would accept a proton and give you the OH- concentration.

Callum Guo 1H
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Re: pH vs. pOH

Postby Callum Guo 1H » Sun Jan 19, 2020 5:28 pm

to calculate pOH. You find the concentration of OH- molecules and then take the -log[OH-] to find the pOH

san_2F
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Joined: Sat Jul 20, 2019 12:15 am

Re: pH vs. pOH

Postby san_2F » Sun Jan 19, 2020 5:31 pm

You know whether you are calculating for a base or for an acid based on whether there is OH being produced or H3O+.

Shail Avasthi 2C
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Joined: Fri Aug 30, 2019 12:17 am

Re: pH vs. pOH

Postby Shail Avasthi 2C » Sun Jan 19, 2020 5:33 pm

You calculate pH and pOH by taking the negative log (-log) of [H3O+] or [OH-]. You typically calculate pH for acids and pOH for bases, but questions will often ask you for pH no matter what. Use pH+pOH=14 to convert from pOH to pH.

lauraxie2e
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Re: pH vs. pOH

Postby lauraxie2e » Sun Jan 19, 2020 5:50 pm

you use the concentration of a base

Veronica Lu 2H
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Re: pH vs. pOH

Postby Veronica Lu 2H » Sun Jan 19, 2020 6:33 pm

to find the pH use the concentration of an acid to find pOH use the concentration of a base. IF given pH you can simply subtract that from 14 to find the pOH

kausalya_1k
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Joined: Wed Nov 14, 2018 12:23 am

Re: pH vs. pOH

Postby kausalya_1k » Sun Jan 19, 2020 6:38 pm

pOH=-log[OH-] and you would use that for bases
pH=-log[H3O+] and you would use this for acids
pH+pOH=14

Tanmay Singhal 1H
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Joined: Sat Jul 20, 2019 12:16 am

Re: pH vs. pOH

Postby Tanmay Singhal 1H » Sun Jan 19, 2020 6:39 pm

pH+pOH=14 and pOH = -log[OH-}

J Medina 2I
Posts: 102
Joined: Wed Sep 25, 2019 12:17 am

Re: pH vs. pOH

Postby J Medina 2I » Sun Jan 19, 2020 6:46 pm

Sometimes certain problems will make it easier to calculate pH, and if the pOH is being asked then you can take the pH (-log(H3O+)) and subtract that value from 14 (since pH + pOH + 14).

005324438
Posts: 51
Joined: Sat Aug 24, 2019 12:16 am

Re: pH vs. pOH

Postby 005324438 » Sun Jan 19, 2020 7:23 pm

p before anything means to take the -Log of that thing. pH and pOH are the -log of the H concentrations and the OH concentrations. We can use the K equation to solve for the concentrations. We know we're solving for pH or pOH depending on if the reaction we are using, whether its a weak base or weak acid, and whether its Ka or Kb.

kevinolvera1j
Posts: 103
Joined: Fri Aug 02, 2019 12:15 am

Re: pH vs. pOH

Postby kevinolvera1j » Sun Jan 19, 2020 7:26 pm

To calculate pOH it is simply =-log[OH-] , and to find pH it is -log[H+] or -log[H30+]. pOH is used to calculate the strength of bases, while pH is used to calculate the strength of acids. To find one if the other is given the equation is pH+pOH=14.

SarahCoufal_1k
Posts: 102
Joined: Thu Jul 25, 2019 12:17 am

Re: pH vs. pOH

Postby SarahCoufal_1k » Sun Jan 19, 2020 7:35 pm

you find pOH by taking the -log[OH- concentration]. you find pH by taking the -log[H30+ concentration].When it is base you use the OH- concentration and when it is an acid you use the H30+ ion concentration. Also when the equation/problem only gives you one, you can find the other because pH + pOH=14


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