Test 1 Practice Worksheet #5

[Emily Vainberg 1D]

Question 5 states: What is the pH of a .030 M solution of NaC6H7O2? The pKa of C6H8O2 is 4.76. C6H7O2-(aq) + H2O(l) ⇔ C6H8O2(aq) + OH-(aq)


For my answer I got the pH= 10.858
Did anyone else do this problem and get the same answer?

[nicolely2F]

Yes, I got 10.86

[Jessica Li 4F]

I actually got 8.6 - I think you forgot to convert the given pKa value to pKb, as the molecule you are dealing with is actually the base.

[Luc Zelissen 1K]

I actually got 8.6 - I think you forgot to convert the given pKa value to pKb, as the molecule you are dealing with is actually the base.

I got the same answer as you!

[Sally Qiu 2E]

i got 8.62

[Junwei Sun 4I]

I got 8.62 too maybe you forget to convert pKa to pKb since C6H7O2-(aq) is a base. And you first calculate pOH and then subtract and get the pH value.

[Emma Popescu 1L]

I also got 8.62. You have to convert pKa to pKb