removing H2 from N2 + 3H2 -> 2NH3
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removing H2 from N2 + 3H2 -> 2NH3
Why does decreasing H2 from the reaction cause NH3 to produce more H2? Wouldn't that just cause there to be a constant amount of H2?
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Re: removing H2 from N2 + 3H2 -> 2NH3
If H2 is removed from this chemical reaction. That means that the Q>K and the reaction will shift toward the reactants. Basically the system wants to compensate for the decrease in H2, so it will produce more reactants (H2 and N2) to raise the amount of H2 back so that Q=K
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Re: removing H2 from N2 + 3H2 -> 2NH3
Decreasing H2 would cause there to be less reactants meaning the equilibrium will shift back towards the reactants in order to maintain the value of K.
Re: removing H2 from N2 + 3H2 -> 2NH3
removing H2 causes an absence of H2 thus causing the reaction to form more H2 since there is an absence of it
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Re: removing H2 from N2 + 3H2 -> 2NH3
Decreasing H2 from the reaction would cause the equilibrium to shift to the left and produce more reactants in order to minimize the effect of that change.
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Re: removing H2 from N2 + 3H2 -> 2NH3
Decreasing H2 in the reaction means overall there are less reactants compared to products and the ratios between products and reactants are not at the equilibrium constant Kc, so inorder to get to the equilibrium ratio, you have to produce more reactants so the reaction shift towards the left, making more H2 as you remove the H2 from the reaction.
Re: removing H2 from N2 + 3H2 -> 2NH3
according to le chatelier's principle, a system works to minimize the effect of the change. therefore there will be an increase in the rate of the reverse reaction, and there will be H2 formed until it reached the required level
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Re: removing H2 from N2 + 3H2 -> 2NH3
Removing H2 would make the reaction shift toward the reactants because of Le Chatlier's, so more N2 would be produced.
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