3 posts • Page 1 of 1
In the example that Dr. Lavelle used during lecture, drawing the Lewis structures reveals that the double bond between the carbons in ch2 is broken since the product (ch3ch2br) only has a single bond between the carbons. You would have to compare the Lewis structures of the reactants and the products separately to see which are broken and which are formed.
Who is online
Users browsing this forum: No registered users and 3 guests