## Homework 4A.9

MaryBanh_2K
Posts: 101
Joined: Wed Sep 18, 2019 12:21 am

### Homework 4A.9

For homework problem 4A.9:
A piece of copper of mass 20.0 g at 100.0 8C is placed in a vessel of negligible heat capacity but containing 50.7 g of water at 22.0 8C. Calculate the final temperature of the water. Assume that no energy is lost to the surroundings.

The solutions manual states that we solve for the final temperature by equaling the heat lost by the metal to the heat gained by the water. However, it also states that the heat gained by the water is negative. Why is it negative in this case? Doesn't a negative q mean that the water is losing heat (exothermic)? Why isn't the heat lost by the metal a negative value?

BNgo_2L
Posts: 95
Joined: Wed Sep 11, 2019 12:17 am

### Re: Homework 4A.9

I think we went over something similar during lecture where Dr. Lavelle said the heat released by a reaction = - heat absorbed by the solution. The negative sign is just referring to the heat being released, which is negative. Heat released = - (heat absorbed), while - (heat released (-)) = heat absorbed.

Shutong Hou_1F
Posts: 117
Joined: Sat Sep 14, 2019 12:17 am

### Re: Homework 4A.9

I think that your reasoning is exactly correct. And I believe that it doesn't matter which side you would like to put the negative sign on. The only thing matter is that one substance is losing heat whereas the other one is gaining heat, so if we set the change in heat of one substance negative, then the other is positive, and vice versa.

MaggieHan1L
Posts: 100
Joined: Thu Jul 11, 2019 12:17 am

### Re: Homework 4A.9

The negative sign is there to help signify the relationship between the two temperatures and it doesn't really matter because you just want to have the right amounts of negatives on both sides.