## 4B.5

Shimei_2F
Posts: 100
Joined: Fri Aug 09, 2019 12:17 am
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### 4B.5

An ideal gas in a cylinder was placed in a heater and gained 5.50 kJ of energy as heat. If the cylinder increased in volume from 345 mL to 1846 mL against an atmospheric pressure of 750. Torr during this process, what is the change in internal energy of the gas in the cylinder?

How do we solve this?

Jessica Booth 2F
Posts: 101
Joined: Fri Aug 30, 2019 12:18 am

### Re: 4B.5

First, U=q+w. So you know that q= 5.50KJ. Then you know that there is a constant pressure so $w= -p\Delta V$.

GFolk_1D
Posts: 101
Joined: Fri Aug 09, 2019 12:15 am

### Re: 4B.5

In this case would it be necessary to convert the pressure from Torr to atm before plugging it into the equation?

christabellej 1F
Posts: 109
Joined: Sat Aug 17, 2019 12:17 am

### Re: 4B.5

Yes, you would want to convert the pressure from Torr first so that the units can match and cancel when you use the internal energy change equation.

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