change in Kc

Moderators: Chem_Mod, Chem_Admin

connie 2C
Posts: 106
Joined: Thu Jul 11, 2019 12:17 am

change in Kc

Postby connie 2C » Wed Feb 12, 2020 12:10 pm

when there is a constant multiplied to the overall chemical equation, how does Kc change? what are the rules for Kc when there is a change to the overall reaction(s)?

Daniela Shatzki 2E
Posts: 53
Joined: Sat Aug 24, 2019 12:16 am

Re: change in Kc

Postby Daniela Shatzki 2E » Wed Feb 12, 2020 12:15 pm

you raise Kc to whatever you multiply by. if you multiply by 2 then Kc = Kc^2, if you divide by 2 / multiply by 1/2 then Kc = Kc^1/2 or square root of Kc.

Jessica Chen 2C
Posts: 103
Joined: Thu Jul 11, 2019 12:17 am

Re: change in Kc

Postby Jessica Chen 2C » Thu Feb 13, 2020 1:24 am

I agree with the previous response. If you think about it, it makes sense because you're changing the coefficient of each reactant/product by the same factor, and the coefficients determine what power the values are raised to. For example, if the overall reaction is multiplied by 2, then each reactant/product in K is raised to the power of 2, and K overall would be raised to the power of 2.

Justin Seok 2A
Posts: 104
Joined: Sat Aug 24, 2019 12:15 am

Re: change in Kc

Postby Justin Seok 2A » Thu Feb 13, 2020 2:38 am

If you reverse the reaction, then Kc becomes 1/Kc. If you multiply the reaction by a constant, Kc equals Kc^x, where x is that constant.

Connor Chappell 2B
Posts: 59
Joined: Wed Feb 20, 2019 12:16 am

Re: change in Kc

Postby Connor Chappell 2B » Thu Feb 13, 2020 8:42 am

Multiplying a reaction by some constant is the mathematical equivalent of raising the power of the Kc of said reaction to that same constant.

Lizette Noriega 1H
Posts: 105
Joined: Wed Sep 18, 2019 12:15 am

Re: change in Kc

Postby Lizette Noriega 1H » Thu Feb 13, 2020 9:23 am

If you were to reverse a reaction, the value for the constant will be the inverse (1/Kc) whereas if you multiply the reaction by some constant, the value of Kc will have to be raised by the same value (Kc^x).


Return to “Equilibrium Constants & Calculating Concentrations”

Who is online

Users browsing this forum: No registered users and 0 guests