reversing reactions

[Kaylee Clarke 1G]

what happens to K when you reverse a reaction?

[Cavalli_1H]

the K of a reverse reaction is the inverse of the forward reaction

[chrisleung-2J]

When a reaction is reversed, K -> 1/K

[Charysa Santos 4G]

The K of a reverse reaction is just the inverse of K (or 1/K)

[505316964]

In a forward reaction, you do products over reactants for the equilibrium equation. For the reverse it is technically reactants over products, so it makes sense that your K would be 1/K for the reverse.

[Jesalynne 2F]

For a reverse reaction the value of K would be 1/K which is the inverse.

[WGaines_2E]

for the reverse reaction lets say Kr, Kr=1/K

[ABombino_2J]

K reverse : 1/k
K*n : K^n
K*m: K^(1/m)

[Jainam Shah 4I]

If you reverse the reaction simply take the reciprocal of the the original K value so 1/K.

[CalvinTNguyen2D]

The value of K in a reverse reaction is the inverse of the forward reaction. If the value of K in a forward reaction is K, then the equilibrium constant in the reverse reaction is 1/K.

[Charlene Datu 2E]

The K of the reverse reaction will be the inverse of the K of the forward reaction
K_reverse = 1/K_forward

A + B -> C
K_forward = [C]/[A][B]
K_reverse = [A][B]/[C]

[aishwarya_atmakuri]

When you reverse the reaction, you have to invert K. Therefore, for a forward reaction, the equilibrium constant is equal to K. For the reverse reaction, the equilibrium constant is equal to 1/K.

[Ellis Song 4I]

The k for a reversed reaction is 1/k

[Jasmine W 1K]

K is inversed so it becomes 1/K.

[ramiro_romero]

K is going to become inverse, so 1/K.

[Adam Bustamante 1I]

In a reverse reaction, K would become inverse, so it would be 1/K.

[Shreyank Kadadi 3K]

The equilibrium constant (K) for a reverse reaction is simply the inverse of the K for the forward reaction. If you think about it logically it makes sense -- a reaction that heavily favors the products would not have much reactants being formed, and vice versa.

[Madison Muggeo 3H]

Hi! In the reverse reaction, it would be 1/K since the fraction is flipped. Hope this helps :)

[Rahul Sobti 1E]

When you reverse a reaction the equilibrium constant becomes the reciprocal of K so it becomes 1/k.

[Jamie Wang 3C]

reverse is 1/K and when multiplied by a constant(n), K^n

[Yeonjoo Kim 2B]

Just like in inverse reactions (x^-1 = 1/x), K becomes 1/K or K^-1

[Jiapeng Han 1C]

For the reverse reaction, k of forward reaction will become 1/k in the reverse reaction.

[Anusha Chaudhary 1J]

For the reaction P <-> R (reversible reaction), [P]/[R] will give us our K value. However, if we reverse what we define as our P and R, we would simply be flipping the equation, so the old R is on top and the old P is on the bottom. This will give us the inverse of our original K value, or simply put, 1/K.

[Maya Johnson 2a]

It becomes the inverse reaction, or 1/K

[sophia kosturos 2B]

For the reverse reaction, K will become its inverse or reciprocal, which is 1/K.

[Lily Anne Garcia 1C]

1/K

[Katie Nye 2F]

K becomes inverted. The way to remember this is that when an equation is reversed, what was once the products (numerator) becomes the reactants (denominator) and vice versa so the K equation would flip.

[Chudi Onyedika 3A]

K will simply become the inverse of the reaction.

[Simi Kapila_3E]

when you take a reverse reaction, you will inverse the K value (1/K) to get the new K value.

[Melis Kasaba 2B]

The equilibrium constant for a reverse reaction is the reciprocal of the one for the forward reaction, so it would be 1/K.

[Jason Knight - 1F]

An easy way to calculate the K value for the reverse reaction is to find the reciprocal of the forward reaction, which is K = (1/Forward). I find this calculation quick and simple instead of flipping the formula to K = (R)/(P) and plugging in values from there.

[Kayla Booker 1F]

When you reverse the reaction, k is inverted so it would then be 1/k or k^-1

[Karen Elrayes 1L]

Reversing the reaction flips all Reactants to products and vice versa, thus when u are calculating K the top and bottom are flipped which is why we put 1/k when we reverse the reaction.

[Carlos Martinez 2K]

K becomes 1/K when you reverse a reaction. This shows that the concentrations are the same during. equilibrium. This. can also be written as K-1

[Mari Williams 1K]

Reverse reaction move towards the reactants, right? Does K only refer to the forward reaction or can we specify K(reverse)

[Hana Sigsbee 3B]

when a reaction is reversed K is inversed as 1/K

[Daniela Santana 2L]

When you reverse a reaction, the K value of it is the inverse of the forward reaction. So to find K for the reverse reaction solve for 1/K.

[Andy Hernandez]

It is just the inverse of K or 1/K

[Adrienne Chan 1G]

We get the inverse of K, this is calculated as 1/K.

[MichaelRaad_1F]

The K of a reverse reaction is the inverse of the K for the forward reaction.

[Karen Zheng_2K]

When you reverse an action, K becomes 1/K!

[joshtully]

When a reaction is reversed, K becomes 1/K.

[Melanie Lin 3E]

Hi! The K of the reverse reaction will be the reciprocal of the K of the forward reaction (1/K).

[Jack Kettering 3D]

The k value for the reversed reaction is just the inverse of k, 1/k

[RaniyaFeroz_1E]

K would just be 1/K when you reverse a reaction. I think Dr.Lavelle had an example of this in his first lecture.

[Isaias Gomez D3A]

When a reaction is reversed, K -> 1/K

just the inverse :)

[Hannah Lechtzin 1K]

The K of a reverse reaction is just the inverse of K (1/K).

[Francesca_Borchardt_2D]

I was confused on this as well, all the above replies really helped me.. Thank you everyone :)!

[Ashley Wagner 2A]

The reverse reaction K value is just the inverse of K for the forward reaction. Therefore it would be 1/K

[Aria Movassaghi 1A]

It would become 1/k

[LeahSWM 2E]

When you reverse the reaction of K, the value becomes 1/K.

[Zihan Liu 2K]

It would be 1/K because in a forward reaction, K = [P]/[R]. In a reverse reaction, the product in the forward reaction would become the reactant in the reverse reaction, and the same goes with the reactant in the forward reaction. Therefore, the K for the reverse reaction equals to [R]/[P]. [R]/[P] is the 1/([P]/[R]). Therefore, it would be 1/K.

[Chinmayi Mutyala 3H]

K is products over reactants so if you use the reverse reaction, K would be the reactants over the products. That's why K (reverse) is 1/K (forward)

[Gustavo_Chavez_1K]

When reversing a reaction, the value of K becomes the inverse of the forward reactions K (1/K).

[Lorraine Medina 3E]

When K is reversed, it becomes the inverse of the forward reaction, therefore 1/K. Hope this helps!

[Akriti Ratti 1H]

In this case, K would be inversed. So it would go from K to 1/K.

[Tiao Tan 3C]

K would also be inversed. It will become 1/K because the equilibrium constant for the inversed reaction is adopting a reversed product-reactant relationship.

[ShinwooKim_3E]

K becomes the inverse, 1/K.

[Sukhkiran Kaur 3I]

It would be inverse K, so 1/K.

[Lung Sheng Liang 3J]

The K for reverse reactions would be 1/K

[Brian Nguyen 2I]

When you reverse a reaction, K is just equal to the reciprocal of K instead. This is 1 divided by K.

[Vivian_Le_1L]

The K of the reverse reaction would be the inverse. 1/K or K^-1.
EX. [A] + [B] <-> [C]
K_FORWARD = [C] / [A][B]
K_REVERSE =[A][B] / [C] , which is the reciprocal/inverse of the forward reaction.

[Megan ODonnell 3F]

It is the inverse of the forward reaction, so you would take 1/K to find the reverse constant.

[Gwen Casillan 3E]

It would be the inverse of K, so 1/K.

[Jared Limqueco 3E]

In a reverse reaction, you take the reciprical, so 1/K

[305405193]

just like how you reversed the reaction, you would have k inversed so it would be 1/K

[305405193]

One good video that expressed an example of reversing a reaction was on this link https://www.youtube.com/watch?v=aJ0KNQ5-KaI

[Bai Rong Lin 2K]

it basically changes k > 1/k.

[Jack Kettering 3D]

K for a reversed reaction is equal to the inverse of the forward reaction's k.

[Mansi Solanki 3A]

When you reverse the reaction, the K now becomes 1/K which would essentially be the inverse of the original K.

[Yeonjoo Kim 2B]

K becomes 1/K or K^-1

[Colin Squire 3B]

When the reaction of K is reversed, K becomes the inverse of the reaction, 1/K.

[alebenavides]

when K is reversed it becomes the inverse

[SahajDole_1C]

When you reverse a reaction, the k value is inversed so it would be 1/K

[Faith Lee 2L]

The K for the reverse reaction is the inverse (1/K) of the forward reaction, and vice versa :)

[Laura 3l]

When you reverse the reaction, K simply becomes the inverse of itself (1/K).

[Faaizah Arshad 1H]

When you reverse a reaction, you should take the inverse of K, which means computing 1/K.

[Cecilia Cisneros 1F]

For a reverse reaction, you should take the inverse of the original K in order to find the equilibrium constant (AKA: new K value)

[Sejal Parsi 3K]

K becomes the inverse: 1/K.

[Samantha Lee 1A]

When you reverse reactions, you are going from products to reactants. Because of that, you would get K = 1/K because K is products over reactants and you would want the reverse, reactants over products because that is the new products/reactants.

Use inverse K (1/k, or K^-1) for a reverse reaction. Think of doing the problem backwards, flip the K.

[Namita Shyam 3G]

When a reaction is reversed, we will get 1/K.

[Gwirnowski 3B]

for the reverse reaction, the inverse of K is used, or 1/K

[Joel Meza 3I]

When you have a reaction A+B-->C and have its K value and then reverse the reaction to C-->A+B, the K value of this reverse reaction will be the inverse of the first K value.

[Tatyana Bonnet 2H]

When you reverse a reaction you take the inverse of K, 1/K, because you are essentially just flipping the products and reactants of the reaction. So in the reverse reaction the products are the reactants from the original reaction and the reactants are the products.