## delta s

$\ln K = -\frac{\Delta H^{\circ}}{RT} + \frac{\Delta S^{\circ}}{R}$

Posts: 134
Joined: Sat Sep 14, 2019 12:17 am

### delta s

Why do we assume delta s naught is constant in the van't hoff equation?

Jonathan Gong 2H
Posts: 105
Joined: Sat Jul 20, 2019 12:16 am

### Re: delta s

delta S naught is the entropy of the reaction at standard conditions. Since standard conditions are defined, delta S naught will be a constant/always have the same value.

Bryce Barbee
Posts: 103
Joined: Wed Sep 18, 2019 12:20 am

### Re: delta s

This is because delta S naught is the standard entropy of that reaction, therefore making it constant. We then have to include the temperature to show how the observed entropy can change depending on how you change the different parameters such as temp.

William Francis 2E
Posts: 101
Joined: Wed Sep 18, 2019 12:20 am

### Re: delta s

ΔS° is defined as entropy change in a set of standard conditions. ΔS° won't change for a given reaction unless those standard conditions do.

VPatankar_2L
Posts: 104
Joined: Thu Jul 25, 2019 12:17 am
Been upvoted: 1 time

### Re: delta s

Delta S is constant in the Vant Hoff equation because the change in entropy of the system at equilibrium is constant. Delta S doesn't increase because it has reached its maximum.

Jacob Villar 2C
Posts: 105
Joined: Sat Aug 17, 2019 12:18 am

### Re: delta s

Delta S won’t change under standard conditions.

Noe BM 1J
Posts: 50
Joined: Sat Sep 07, 2019 12:17 am

### Re: delta s

It won't change unless standard conditions are changed

sarahartzell1A
Posts: 56
Joined: Fri Sep 28, 2018 12:17 am

### Re: delta s

Because delta s won't change in those conditions!

rabiasumar2E
Posts: 108
Joined: Thu Jul 11, 2019 12:15 am

### Re: delta s

Because standard conditions don't change !

rohun2H
Posts: 100
Joined: Wed Sep 18, 2019 12:19 am

### Re: delta s

Delta s does not change, both s values may change but the difference between final and intitial remains constant.