## Exothermic rxns being spontaneous

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

205192823
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### Exothermic rxns being spontaneous

Why are most exothermic reactions spontaneous?

chemboi
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### Re: Exothermic rxns being spontaneous

Spontaneity is determined by the sign of G, where G = H - T*S. For exothermic reactions., H is negative, so it is more common for G to be negative as well (S is positive, or negative T*S term is lower in absolute value than H)

Joowon Seo 3A
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### Re: Exothermic rxns being spontaneous

Spontaneity means that the change in gibbs free energy is negative. Most exothermic reactions have a decrease in enthalpy meaning an increase in heat to the surroundings as well as an increase in entropy

saigorijavolu2k
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### Re: Exothermic rxns being spontaneous

Spontaneous reactions have negative gibbs free energy. G= H-TS (include the deltas). If H is negative (exo) then the likelihood of the overall reaction being negative increases as long as entropy is positive. if entropy is negative then H (-H in this case) must be greater than TS

Sanjana K - 2F
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### Re: Exothermic rxns being spontaneous

Although reactions being exothermic/endothermic and spontaneous/nonspontaneous are closely related, you should also keep in mind that not all exothermic reactions will be spontaneous. When checking for spontaneity, look at the delta G sign (meaning you need the sign of delta H AND the sign of delta S and whether the temp is high/low) and when looking at whether or not heat is released, look at the delta H sign only. An example of heat released not corresponding to spontaneity is the condensation of steam.

Kevin Antony 2B
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### Re: Exothermic rxns being spontaneous

Spontaneous reactions are characterized by having a deltaG. When a reaction gives off heat(exothermic) that means that H is negative. Now, unless S is positive, deltaG will be negative as deltaG = deltaH - T(deltaS).