## homework question 6L.1

$\Delta G^{\circ} = -nFE_{cell}^{\circ}$

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Joined: Tue Sep 10, 2019 12:16 am

### homework question 6L.1

calculate the standard reaction gibbs free energy for the following cells:
(a) 2 Ce^4+ (aq) + 3I^- (aq) > 2 Ce^3+ (aq) + I3^- (aq), Ecell = +1.08V
(b) 6 Fe^3+ (aq) + 2 Cr^3+ (aq) + 7 H20 (l) > 6 Fe^2+ (aq) + Cr2o7^2- (aq) + 14 H+ (aq), Ecell = -1.29V

Alexis Webb 2B
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Joined: Thu Jul 11, 2019 12:15 am

### Re: homework question 6L.1

For this question, you use the equation standard delta G of the reaction= -nFE. All you do is plug in all the variables. E is given, F is a constant, and n is the number of moles of the reaction.

Posts: 102
Joined: Wed Sep 18, 2019 12:18 am

### Re: homework question 6L.1

Keep in mind, however, that in order to answer the question correctly, you must write out the half-reactions for both part a and part b. This will allow you to determine how many moles of electrons were transferred, n. Otherwise, all the other needed pieces of information are given.

Rodrigo2J
Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

### Re: homework question 6L.1

First, you have to find the moles of electrons being transferred by writing out the half reactions. Then you need to substitute all your known values into the equation delta G= -nFE.

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