## Slopes of a plot

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

JulieAljamal1E
Posts: 71
Joined: Fri Sep 28, 2018 12:24 am

### Slopes of a plot

Is the slope of a plot of a first order negative?

Meghanhe1l
Posts: 60
Joined: Fri Sep 28, 2018 12:17 am

### Re: Slopes of a plot

yes it is

Gillian Ward 1F
Posts: 61
Joined: Fri Sep 28, 2018 12:27 am

### Re: Slopes of a plot

Since first order is ln[A]=-kt+ln[A]o it has a negative slope due to the -k.

SydBenedict2H
Posts: 60
Joined: Wed Nov 08, 2017 3:00 am

### Re: Slopes of a plot

The only one that isn't -k is is 2nd-order, which is just k (+k).

Giselle1B
Posts: 26
Joined: Fri Sep 28, 2018 12:19 am

### Re: Slopes of a plot

Zero Order also has a negative slope. Think of the equations as mx+b. The Slope (mx) is similar to kt in the order process formulas.

Douglas Nguyen 2J
Posts: 71
Joined: Fri Sep 28, 2018 12:15 am

### Re: Slopes of a plot

Yes, both zero and first order reactions' linear plots have slope as -k.

Kate Swertfager
Posts: 50
Joined: Wed Sep 18, 2019 12:17 am

### Re: Slopes of a plot

Yes the graph of the first order has a negative slope. The slope is -k and since k is always positive the slope is always negative for 1st order.