HW 6L.7 (c)

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HW 6L.7 (c)

Postby Shimei_2F » Sat Feb 29, 2020 12:07 am

Problem asks to write the half-reactions and devise a galvanic cell (write a cell diagram) to study each of the following reactions.

(c) Cd(s) + 2Ni(OH)3(s) --> Cd(OH)2(s) + 2Ni(OH)2(s), the reaction in nickel-cadmium cell

I found the two half-reactions which were:
Cd(s) + 2OH-(aq) --> Cd(OH)2 + 2e-
2Ni(OH)3(s) + 2e- --> 2Ni(OH)2(s) +2OH-(aq)

When I compared my cell diagram to the solutions manual, the solution manual had: Cd(s)|Cd(OH)2(s)|KOH(aq)||Ni(OH)3(s)|Ni(OH)2(s)|Ni(s)

Where did the KOH(aq) come from?

Jessica Li 4F
Posts: 115
Joined: Fri Aug 09, 2019 12:16 am

Re: HW 6L.7 (c)

Postby Jessica Li 4F » Sat Feb 29, 2020 9:14 am

I believe KOH is just a neutral form of the OH- ion involved in one of the half reactions - I'm not sure if you actually need to include the KOH or if just OH- is fine.

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