Comparing Experimental Data

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AGaeta_2C
Posts: 112
Joined: Wed Sep 18, 2019 12:21 am

Comparing Experimental Data

Postby AGaeta_2C » Sun Mar 01, 2020 9:20 pm

On Friday, Professor Lavelle went over the strategy for finding the overall reaction order by comparing experimental data provided in the question. On the slide it said:
(RATE 2/RATE 1) = 2 = 2.0m therefore m=1

I understand why m would equal 1 but I'm struggling to see where the expression 2.0m came from... Can anyone help? Thank you!

Kate Osborne 1H
Posts: 102
Joined: Fri Aug 30, 2019 12:16 am

Re: Comparing Experimental Data

Postby Kate Osborne 1H » Sun Mar 01, 2020 9:23 pm

the concentration doubled for one of the reactants and the rate doubled so to find the order you use the equation: change in rate = change in concentration ^ order where you are solving for the order

BNgo_2L
Posts: 95
Joined: Wed Sep 11, 2019 12:17 am

Re: Comparing Experimental Data

Postby BNgo_2L » Wed Mar 04, 2020 8:53 pm

2.0^m comes from [rate 2's R]^m/[rate 1's R]^m after cancelling out all the constants --> ([rate 2's R]/[rate 1's R])^m = 2.0^m

gabbymaraziti
Posts: 111
Joined: Wed Sep 18, 2019 12:19 am

Re: Comparing Experimental Data

Postby gabbymaraziti » Thu Mar 05, 2020 4:36 pm

We created a ratio of concentration 2/concentration 1, both of which were raised to the power of m. 2.0 was the value of that ratio (2.0^m). The ratio of the actual rates was also 2, so m must be 1.


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