Self Test 6L.3

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Self Test 6L.3

Postby gabbymaraziti » Sun Mar 01, 2020 10:34 pm

I don't understand how the textbook found this answer. The questions asks us to write the chemical equation corresponding to a cell, and I found the correct oxidation and reduction equations, but not the correct full equation.

reduction : Hg2(NO3)2 + 2e- --> 2Hg + 2NO3-
oxidation : 2Hg + 2HCl --> Hg2Cl2 + 2e-
The textbook says that the final equation should be 2HCl + Hg2(NO3)2 --> Hg2Cl2 + 2HNO3,
But the equation that I see is 2HCl + Hg2(NO3)2 --> Hg2Cl2 + 2NO3-.

Where did the textbook find this final part of the equation??

connie 2C
Posts: 106
Joined: Thu Jul 11, 2019 12:17 am

Re: Self Test 6L.3

Postby connie 2C » Mon Mar 02, 2020 12:06 am

the reactant side of your equation has a H but your product side doesn't. the correct chemical equation includes the H but i'm not sure how they came to that conclusion of the last molecule sorry

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