## 7A.15

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

ayushibanerjee06
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### 7A.15

For 7A.15 a), how are we supposed to find the values of m and n when [C] is constantly changing?

Diana_Diep2I
Posts: 130
Joined: Sat Aug 17, 2019 12:17 am

### Re: 7A.15

When you find the ratio between Rate 1 and Rate 4, you will see that [C] will be in zeroth order. That means that now the differential rate law is k[A][B]. Now, when finding the orders of A and B, you don't need to take into account [C] because the reaction does not depend on the concentration of [C].

Megan Vu 1J
Posts: 101
Joined: Thu Jul 25, 2019 12:15 am

### Re: 7A.15

In figuring out the answer, you would see that the concentration of C would be changing, but you do not take it into account since it is a zero order. The differential rate law would instead be rate = k[A][B] instead, so this way, you are able to focus on the differences between each experiment from concentrations of A and B. This would make analysis much more straightforward in comparison so you're able to determine the orders for each.

BeylemZ-1B
Posts: 95
Joined: Thu Jul 25, 2019 12:17 am

### Re: 7A.15

How are you supposed to know something is Zeroth order? is there a specific rule to know that it is zeroth order?