finding n in G=-nFE
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Re: finding n in G=-nFE
n is the number of electron transferred which can be found when you balance the redox reaction.
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Re: finding n in G=-nFE
When you find the half reactions, n is the least common multiple of their shared electrons. So you would have to balance them. (Usually n is either 1 or 2).
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Re: finding n in G=-nFE
You can find n when you are balancing your redox reaction. n is the moles of electrons being transferred in the balanced reaction.
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Re: finding n in G=-nFE
When you write and balance the half-reactions, the mols of electrons (should be balanced to be the same in both equations) is the number you use as n in the equation.
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Re: finding n in G=-nFE
To find n you balance the redox reaction to determine the number of moles of electrons being transferred during the reaction.
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Re: finding n in G=-nFE
For example in a redox eq like Cu2+ + 2e- ---> Cu, n would be 2 since 2 electrons sre being transferred.
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Re: finding n in G=-nFE
After you balance the redox reaction, the number of electrons in the overall reaction is n.
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Re: finding n in G=-nFE
n is the number of electrons exchanged in the general reaction. So you look at the oxidation numbers, and then you look at how they have changed.
Re: finding n in G=-nFE
use the highest number of moles of electrons transferred according to the half reactions
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Re: finding n in G=-nFE
You need to write out the half reactions first. When you combine the half reactions, n is the number of electrons on either side of the equation (they cancel each other out).
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Re: finding n in G=-nFE
Hannah_1G wrote:How do you find n?
"n" is found by finding the two half reactions, and balancing them.
When balancing the half reactions, in order to balance the two half reaction charges, you will add electrons. The number of electrons in the reaction is the value of "n".
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Re: finding n in G=-nFE
you can find n after balancing the half rxns. the number of e- should cancel out and that number = n
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