## 7A3

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

lauraxie2e
Posts: 108
Joined: Fri Aug 09, 2019 12:17 am

### 7A3

Aren't the answers supposed to be opposite of each other because one is rate of formation and one is rate of consumption?

Samuel Tzeng 1B
Posts: 103
Joined: Sat Aug 24, 2019 12:15 am

### Re: 7A3

Since the equation has 3 moles of O2 on the reactant side, the rate at which oxygen reacts will be 3 times the rate of reaction
Similarly, since the equation has 2moles of H2O on the product side, the rate at which water forms will be 2 times the rate of reaction

BeylemZ-1B
Posts: 95
Joined: Thu Jul 25, 2019 12:17 am

### Re: 7A3

we know from the unique rate equations for a reaction:
aA + bB --> cC + dD

the rate = -(1/a)d[A]/dt, -(1/b)d[B]/dt, (1/c)d[C]/dt, (1/d)d[D]/dt.
The stoichiometric coeff goes on denominator of the rate of production or consumption. I think this should help you.