## overall order

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

aphung1E
Posts: 101
Joined: Sat Aug 24, 2019 12:15 am

### overall order

How do you calculate the overall order?

Samuel Tzeng 1B
Posts: 103
Joined: Sat Aug 24, 2019 12:15 am

### Re: overall order

You'll have to find the order of the individual reactants then add them up

AKatukota
Posts: 100
Joined: Thu Jul 25, 2019 12:18 am

### Re: overall order

You just add up the individual orders. So if you have A + B --> C and reactant A is order 1 and reactant B is order 2, the overall order would be 3

Betania Hernandez 2E
Posts: 107
Joined: Fri Aug 02, 2019 12:15 am

### Re: overall order

The overall order is just the sum of all the powers of the reactants in the rate law. Such as Rate=k[A]^2[B]^1 has an overall order of 3

805097738
Posts: 180
Joined: Wed Sep 18, 2019 12:20 am

### Re: overall order

the overall order is equal to the sum of all the orders of the reactants. The order of each reactant is the exponential value of the reactant

Megan Cao 1I
Posts: 103
Joined: Sat Sep 07, 2019 12:18 am

### Re: overall order

to calculate the overall order of a reaction you would add the exponents of the reactants.

for example, if the rate law =k[A]2[B]1, then the overall order would be 3 (2+1)